$$ \begin{aligned}\frac{2u-23}{2u^2-25u+23}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{u-1}\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2u-23}$. $$ \begin{aligned} \frac{2u-23}{2u^2-25u+23} & =\frac{ 1 \cdot \color{blue}{ \left( 2u-23 \right) }}{ \left( u-1 \right) \cdot \color{blue}{ \left( 2u-23 \right) }} = \\[1ex] &= \frac{1}{u-1} \end{aligned} $$ |